ajax 传值需注意去掉空格

		function addRoll(){
			
			var content = $.trim($('#content').val());
			var status = $.trim($('#status').val());
			var pwd = $.trim($('#pwd').val());
		//	alert("content:"+content);
			$.ajax({
				url:"http://localhost:8080/kkEBS/i.jsp",
				type:"POST",
			//	dataType:"json",
				data:{'intface':'aroll','content':content,'status':status,'pwd':pwd},
				success:function(res){
					if($.trim(res)=="OK"){
						alert("操作成功");
					}else{
						alert("操作失败");
					}
				},
				error:function(x,e){
					alert(x.responseText+e);
				}
			});
		}

 后台代码:

/** 此处需要鉴权 */
			String content = out.getParameterNPK("content");
			String status = out.getParameterNPK("status");
			String pwd = out.getParameterNPK("pwd");
			String str = addRoll(content, status, pwd);
			if(Wregex.eregi("OK", str)){
				out.print("OK");
			}else{
				out.print(str);
			}
			

 后台传递值“OK”一直不能接收,后找到原因是空格或换行问题,用jquery $.trim()去掉即可

猜你喜欢

转载自sziitjiang.iteye.com/blog/1596369