Codeforces 1189A Keanu Reeves

题目链接:http://codeforces.com/problemset/problem/1189/A


思路:统计1 和 0 的个数,不相等拆开字符串,否则不拆。

AC代码:

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int n;
 6     string a;
 7     while(cin >> n)
 8     {
 9         cin >> a;
10         int s1= 0,s0 = 0;
11         for(int i = 0;i < n;i++)
12         {
13             if(a[i] == '1') s1++;
14             else s0++;
15         }
16         if(s0 != s1) cout << 1 << endl <<  a << endl;
17         else{
18             cout << 2 << endl;
19             cout << a[0] << " ";
20             for(int i = 1;i < n;i++)
21             {
22                 cout << a[i];
23             }
24             cout << endl;
25         }
26     }
27     return 0;
28 }

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转载自www.cnblogs.com/Carered/p/11165860.html