最近由于需要再研究jquery easyui 和tomcat, 今后会逐渐整理一些工作中遇到的问题及其相应的解决方法.
1 easyui 中对json的支持: $('#test').datagrid({
title:'用户信息',
//iconCls:'icon-save',
width:740,
height:400,
nowrap: true,
autoRowHeight: false,
striped: true,
collapsible:true,
url:'<%=request.getContextPath()%>/Worker.do?role=sys&method=querydatagraddata3',
改url返回的是json格式数据[{"total":100,"rows":[{"col5":40,"col4":"192.168.1.1","name":"东辛采油厂40","addr":"2013-07-19","code":"040","newid":"0040"},{"col5":49,"col4":"192.168.1.1","name":"东辛采油厂49","addr":"2013-07-19","code":"049","newid":"0049"}]}]
该结果不能直接返回,需要将头尾的[和]截取掉才能正确返回前台
工作行程
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转载自ycscsjj-126-com.iteye.com/blog/1912118
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