由于在参加大疆的考试，所以完成了大疆的考试，8.20进入了考场，少了一个多小时。

网易游戏的题目还算简单。

第一题

缴税问题，小于5000元不交税，否则（工资-5000）为需要缴税的部分，然后分批次计算缴税费用。

import sys
n = int(sys.stdin.readline().strip())
for i in range(n):
    v = int(sys.stdin.readline().strip())
    m = 0
    if v <= 5000:
        print(str(m))
    else:
        v = v - 5000
        if v <= 3000:
            m += v * 0.03
        elif v > 3000 and v <= 12000:
            m += (3000*0.03 + (v-3000)*0.1)
        elif v > 12000 and v <= 25000:
            m += (3000*0.03 + (12000-3000)*0.1 + (v-12000)*0.2)
        elif v > 25000 and v <= 35000:
            m += (3000*0.03 + (12000-3000)*0.1 + (25000-12000)*0.2 + (v-25000)*0.25)
        elif v > 35000 and v <= 55000:
            m += (3000*0.03 + (12000-3000)*0.1 + (25000-12000)*0.2 
                  + (35000-25000)*0.25 + (v-35000)*0.3)
        elif v > 55000 and v <= 80000:
            m += (3000*0.03 + (12000-3000)*0.1 + (25000-12000)*0.2 
                  + (35000-25000)*0.25 + (55000-35000)*0.3 + (v-55000)*0.35)
        else:
            m += (3000*0.03 + (12000-3000)*0.1 + (25000-12000)*0.2 
                  + (35000-25000)*0.25 + (55000-35000)*0.3 + (80000-55000)*0.35 
                  + (v-80000)*0.45)
        m = int(m+0.5)
        print(str(m))

第二题

字符串的缩写，连续递增的字符串比如‘ABCD’，改为‘A-D’，要求递增的字符大于四个。

AC50%，好像是时间复杂度过大，答主也不知道是什么问题，求解？

import sys

n = int(sys.stdin.readline().strip())
for i in range(n):
    v = sys.stdin.readline().strip()
    res = ''
    l, r, i = 0, 0, 0
    while i < len(v):
        if i < len(v)-1 and ord(v[i]) == ord(v[i+1]) - 1:
            l = i
            r = i + 1
            j = i
            j += 1

            while j < len(v)-1 and ord(v[j]) == ord(v[j+1]) - 1:
                r = j + 1
                j += 1
            if r - l >= 3:
                res += v[l] 
                res += '-'
                i = r


        res += v[i]
        i += 1

    print(res)

第三题没有来得及看。。。