The string "PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string s, int numRows);
Example 1:
Input: s = "PAYPALISHIRING", numRows = 3 Output: "PAHNAPLSIIGYIR"
Example 2:
Input: s = "PAYPALISHIRING", numRows = 4 Output: "PINALSIGYAHRPI" Explanation: P I N A L S I G Y A H R P I
这个没啥说的了,办法太多了。
class Solution {
public:
int function_x(int max,int x)
{
return x<max?x:((max-1)<<1)-x;
}
string convert(string s, int numRows) {
if(numRows==1)
return s;
vector<string> out(numRows);
for(int i=0;i<s.size();i++)
out[function_x(numRows,i%((numRows-1)<<1))] += s[i];
string result;
for(int i = 0;i<out.size();i++)
result += out[i];
return result;
}
};