题目描述
本题要求实现一个计算复数之积的简单函数。
函数接口定义:
struct complex multiply(struct complex x, struct complex y);
其中struct complex是复数结构体,其定义如下:
struct complex
{
int real;
int imag;
};
裁判测试程序样例:
#include <stdio.h>
struct complex
{
int real;
int imag;
};
struct complex multiply(struct complex x, struct complex y);
int main()
{
struct complex product, x, y;
scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
product = multiply(x, y);
printf("(%d+%di) * (%d+%di) = %d + %di\n", x.real, x.imag, y.real, y.imag, product.real, product.imag);
return 0;
}
/* 你的代码将被嵌在这里 */
样例输入 Copy
3 4 5 6
样例输出 Copy
(3+4i) * (5+6i) = -9 + 38i
代码
struct complex multiply(struct complex x, struct complex y)
{
struct complex answer;
answer.real=x.real*y.real-x.imag*y.imag;
answer.imag=x.imag*y.real+x.real*y.imag;
return answer;
}