Problem Description:
读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.
Input:
测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.
Output:
对每个测试用例输出1行,即A+B的值.
Sample Input:
one + two =
three four + five six =
zero seven + eight nine =
zero + zero =
Sample Output:
3
90
96
解题思路:
这道题我们可以利用样例中的“+”和“=”来作为分隔符,用scanf去读入,因为这样就可以被中间的空格给中断,然后用strcmp进行比较就可以了,比较成功的将其转换成数字进行计算即可。具体的我们看代码
程序代码:
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
char a[10][6]={"zero","one","two","three","four","five","six","seven","eight","nine"};
int ans(char ch[])
{
for(int i=0;i<10;i++)
if(strcmp(ch,a[i])==0)
return i;
}
int main()
{
char b[50],c[50];
while(1)
{
int x=0,y=0;
while(scanf("%s",b)&&strcmp(b,"+")!=0)
x=x*10+ans(b);
while(scanf("%s",c)&&strcmp(c,"=")!=0)
y=y*10+ans(c);
if(x==0&&y==0)
return 0;
else
printf("%d\n",x+y);
}
return 0;
}