013元组:带上枷锁的列表

元组和列表的不同

创建一个元组()

>>> tuple = (1,2,3,4,5,6,7,8)
>>> tuple[1]
2
>>> tuple[5:]
(6, 7, 8)
>>> b = (1,2,3)#有小括号有逗号,就可以创建元组
>>> type(b)
<class 'tuple'>
>>> a = 1,2,3,4#没有小括号但是有逗号,也可以创建元组
>>> type(a)
<class 'tuple'>
>>> c = (1)
>>> type(c)
<class 'int'>#比较c和d
>>> d = (1,)
>>> type(d)
<class 'tuple'>#逗号很关键
>>> 8 * (8)
64
>>> 8 * (8,)#再次证明逗号的决定性作用
(8, 8, 8, 8, 8, 8, 8, 8)

元组不可以任意的修改

>>> tuple[1] = 10
Traceback (most recent call last):
  File "<pyshell#3>", line 1, in <module>
    tuple[1] = 10
TypeError: 'tuple' object does not support item assignment

更新删除一个元组

>>> a = ("一","二","三","四")
>>> type (a)
<class 'tuple'>
>>> a = a[:2] + ("伞") + a[2:]
Traceback (most recent call last):
  File "<pyshell#24>", line 1, in <module>
    a = a[:2] + ("伞") + a[2:]#你看,这里的伞没有加逗号,就不是元组,然后就报错了
TypeError: can only concatenate tuple (not "str") to tuple
>>> a = a[:2] + ("伞",) + a[2:]#通过切片方式就把元组拼接起来
>>> a
('一', '二', '伞', '三', '四')

删除就不用了,python会智能的把不用的回收

发布了42 篇原创文章 · 获赞 0 · 访问量 297

猜你喜欢

转载自blog.csdn.net/qq_43169516/article/details/103155696