简化javaSE中繁琐的Scanner及system.out.print结合

使用io流读取控制台输入的信息

避免了繁琐的

System.out.println("请输入数字:")
Scanner input = new Scanner(System.in);
int a = input.nextInt();

System.out.println("请输入字符串:")
String b = input.next();

//...

//很恶心,繁琐
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

/**
 * <p>ClassName: InputUtils</p>
 * <p>Description: </p> 
 * @author gangye
 * @date 2018年12月24日 下午4:48:20 
 */

public class InputUtils {
	private static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
	
	//接收控制台输入的int值
	public static int inputInt(String msg) {
		//输出提示信息
		System.out.println(msg);
		int input = -1;
		try {
			String line = br.readLine();
			input = Integer.valueOf(line);
		} catch (IOException e) {
			e.printStackTrace();
		} catch (Exception e) {
			System.out.println("输入的不是数字,请重新输入!");
			//出现异常后,提示用户继续操作
			return inputInt(msg);
		}
		return input;
	}
	//接收控制台输入的long值
		public static long inputLong(String msg) {
			//输出提示信息
			System.out.println(msg);
			long input = -1;
			try {
				String line = br.readLine();
				input = Long.valueOf(line);
			} catch (IOException e) {
				e.printStackTrace();
			} catch (Exception e) {
				System.out.println("输入的不是数字,请重新输入!");
				//出现异常后,提示用户继续操作
				return inputLong(msg);
			}
			return input;
		}
	
	//接收控制台输入的double值
	public static double inputDouble(String msg) {
		//输出提示信息
		System.out.println(msg);
		double input = -1;
		try {
			String line = br.readLine();
			input = Double.valueOf(line);
		} catch (IOException e) {
			e.printStackTrace();
		} catch (Exception e) {
			System.out.println("输入的不是数字,请重新输入!");
			//出现异常后,提示用户继续操作
			return inputDouble(msg);
		}
		return input;
	}
	
	//接收控制台输入的float值
		public static float inputFloat(String msg) {
			//输出提示信息
			System.out.println(msg);
			float input = -1;
			try {
				String line = br.readLine();
				input = Float.valueOf(line);
			} catch (IOException e) {
				e.printStackTrace();
			} catch (Exception e) {
				System.out.println("输入的不是数字,请重新输入!");
				//出现异常后,提示用户继续操作
				return inputFloat(msg);
			}
			return input;
		}
	
	//接收控制台输入的String值
		public static String inputString(String msg) {
			//输出提示信息
			System.out.println(msg);
			String input = null;
			try {
				input = br.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			} 
			return input;
		}
	
	
}
发布了14 篇原创文章 · 获赞 19 · 访问量 1万+

猜你喜欢

转载自blog.csdn.net/xibei19921101/article/details/86737542