获取相应头

获取响应头之urllib(request)

from urllib import request

req = request.Request('https://jobs.zhaopin.com/CC156559324J00169783014.htm')
r = request.urlopen(req)
m = r.info()   
print(type(m

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转载自blog.csdn.net/Mwyldnje2003/article/details/103406015