CF1B-Spreadsheets
题意:26进制与10进制的转换
代码实现:
#include<bits/stdc++.h> using namespace std; int main(void){ int t; cin >> t; while(t--){ string s; cin >> s; int len = s.size(); bool flag = 0;//flag 用来标志哪种串 for(int i = len-1; i >= 0; i--){ if(isalpha(s[i])&&isdigit(s[i-1])&&isdigit(s[i+1])){ flag = 1; break; } } if(flag){//是R---C--- int sum1 = 0; int i; for(i = 1; isdigit(s[i]); i++){ sum1 = sum1*10+(s[i]-'0'); } int sum2 = 0; for(i = i+1; i < len; i++){ sum2 = sum2*10+(s[i]-'0'); } // 取出数字 stack<char> st; while(sum2){ int t = sum2%26; if(t==0){ //特别注意Z这种情况 st.push('Z'); sum2--; } else st.push(t-1+'A'); sum2 /= 26; } while(!st.empty()){ cout<<st.top(); st.pop(); } cout<<sum1<<endl; }else{ int sum1 = 0; int i; for(i = 0; isalpha(s[i]); i++){ sum1 = sum1*26 + (s[i]-'A'+1); } int sum2 = 0; for(i; i < len; i++){ sum2 = sum2*10+(s[i]-'0'); } cout<<'R'<<sum2<<'C'<<sum1<<endl; } } return 0; }