要求：
http://codeup.cn/problem.php?cid=100000588&pid=12
说明：
这一题在保存两个数的时候纠结了一会
代码：

#include <stdio.h>
#include <math.h>
#include <iostream>
#include <string.h>
using namespace std;

int num[33000];
int record[66000];
void F(int n,int i,int record[]){
	int min,max;
	int gianal = n;
	if(gianal %4 != 0){
		min = n/4;
		n = n%4;
		if(n % 2 == 0){
			min = min + n/2;
			record[i] = min;
		}
		else{
			record[i] = 0;
		}	
	}
	if(gianal %4 == 0){
		min = gianal/4;
		record[i] = min;
	}
	if(gianal %2 != 0){
		record[i+1] = 0;
	}
	if(gianal %2 == 0){
		max = gianal/2;
		record[i+1] = max;
	}
}

int main(){
	int n;
	while(scanf("%d",&n) != EOF){
		for(int i = 1;i < 2*n;i += 2){
			scanf("%d",&num[i]);
			F(num[i],i,record);
		}
		for(int j = 1;j < 2*n;j += 2){
			printf("%d %d\n",record[j],record[j+1]);
		}
		memset(num,0,sizeof(num));
		memset(record,0,sizeof(record));
	}
}