递归
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int mysum(TreeNode* root, int sum)
{
if (!root) return 0;
else if (!root->left && !root->right) return sum * 10 + root->val;
return mysum(root->left, sum * 10 + root->val) + mysum(root->right, sum * 10 + root->val);
}
int sumNumbers(TreeNode* root) {
int sum = 0;
return mysum(root, sum);
}
};