Description
给定当前的时间,请用英文的读法将它读出来。
时间用时h和分m表示,在英文的读法中,读一个时间的方法是:
如果m为0,则将时读出来,然后加上“o'clock”,如3:00读作“three o'clock”。
如果m不为0,则将时读出来,然后将分读出来,如5:30读作“five thirty”。
时和分的读法使用的是英文数字的读法,其中0~20读作:
0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。
30读作thirty,40读作forty,50读作fifty。
对于大于20小于60的数字,首先读整十的数,然后再加上个位数。如31首先读30再加1的读法,读作“thirty one”。
按上面的规则21:54读作“twenty one fifty four”,9:07读作“nine seven”,0:15读作“zero fifteen”。
Input
输入包含两个非负整数h和m,表示时间的时和分。非零的数字前没有前导0。h小于24,m小于60。
Output
输出时间时刻的英文。
Sample Input
0 15
Sample Output
zero fifteen
1 #include<iostream>
2 using namespace std;
3 int h,m;
4 string minute[103]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty"};
5 string ten[103]={" "," ","twenty","thirty","forty","fifty"};
6 int main(){
7 int a,b;
8 cin>>h>>m;
9 if(h<=20)
10 cout<<minute[h]<<' ';
11 else{
12 a=h%10;
13 b=h-a;
14 cout<<ten[b/10]<<' ';
15 cout<<minute[a]<<' ';
16 }
17 if(m==0){
18 cout<<"o'clock";
19 }
20 else if(m>=1&&m<=20){
21 cout<<minute[m];
22 }
23 else{
24 a=m%10;
25 b=m-a;
26 cout<<ten[b/10]<<' ';
27 cout<<minute[a];
28 }
29 return 0;
30 }
就是照着题目去模拟