首页
移动开发
物联网
服务端
编程语言
企业开发
数据库
业界资讯
其他
搜索
Codeforces Round #617 (Div. 3) A. Array with Odd Sum
其他
2020-02-09 22:17:30
阅读次数: 0
题意:是否可以得到一个奇数和,而且我们可以让a(i)=a(j)
题解:直接求和,和数奇数偶数的个数
猜你喜欢
转载自
www.cnblogs.com/RE-TLE/p/12289030.html
Codeforces Round #617 (Div. 3)A. Array with Odd Sum
Codeforces Round #617 (Div. 3) A. Array with Odd Sum
Codeforces Round #617 (Div. 3), problem: (A) Array with Odd Sum 【math】
Codeforces Round #617 (Div. 3) A Array with Odd Sum B Food Buying C Yet Another Walking Robot
Codeforces Round #575 (Div. 3) B - Odd Sum Segments
Educational Codeforces Round 84 (Rated for Div. 2) A. Sum of Odd Integers(思维题)
Educational Codeforces Round 84 (Rated for Div. 2) A. Sum of Odd Integers
Educational Codeforces Round 84 ( Div. 2)A. Sum of Odd Integers
Codeforces Round #702 (Div. 3)——A. Dense Array
【寒假CodeForces】A. Array with Odd Sum 题解
A. Array with Odd Sum
Codeforces Round #617 (Div. 3)
Codeforces Round #617 (Div. 3)题解
Codeforces Round #617 (Div. 3) A~D
Codeforces Round #617 (Div. 3) 题解
Codeforces Round #617 (Div. 3)(题解)
Codeforces Round #617 (Div. 3) (A ~ F)
Codeforces Round #617 (Div. 3) Editorial
Codeforces Round #617 (Div. 3)(A~D)
Codeforces Round #624 (Div. 3)A. Add Odd or Subtract Even
Codeforces Round #624 (Div. 3) A. Add Odd or Subtract Even(水题)
Educational Codeforces Round 84 (Rated for Div. 2) - Codeforces1327 A. Sum of Odd Integers - 水题
Codeforces Round #575 (Div. 3) B. Odd Sum Segments (构造,数学)
Codeforces Round #575 (Div. 3) B. Odd Sum Segments 、C Robot Breakout
Codeforces Round #575 (Div. 3) B. Odd Sum Segments (数学)
Codeforces Round #575 (Div. 3) 1196B. Odd Sum Segments 数学思维
Codeforces Round #575 (Div. 3) 1196B. Odd Sum Segments 数学思维
Codeforces Round #210 (Div. 1) A. Levko and Array Recovery
Codeforces Round #489 (Div. 2) ---- A. Nastya and an Array
Codeforces Round #697 (Div. 3), problem: (A) Odd Divisor,
今日推荐
周排行
Java基础系列-Java11特性解读
前端面试查漏补缺--(十一) 前端软件架构模式MVC/MVP/MVVM
java Listener监听器
矩阵的迹
运用MVP实现二级联动
019基于JSP的学生考勤管理系统(MySQL版)
一道逻辑题 - 我拿走了哪个数
C# 通用单例窗体类
分布式之消息队列复习精讲【转】
Mac 使用.bash_profile
每日归档
更多
2024-07-11(0)
2024-07-10(0)
2024-07-09(0)
2024-07-08(0)
2024-07-07(0)
2024-07-06(0)
2024-07-05(0)
2024-07-04(0)
2024-07-03(0)
2024-07-02(0)