#include<stdio.h>
int a[100010];
int main()
{
int n,i;
scanf("%d",&n);
for(i=1;i<=n;i++)
scanf("%d",&a[i]);
if(n%2==0)
{
if((a[n/2]+a[n/2+1])%2==1)
a[1]>a[n]?printf("%d %.1f %d",a[1],(double)(a[n/2]+a[n/2+1])/2.0,a[n]):printf("%d %.1f %d",a[n],(double)(a[n/2]+a[n/2+1])/2.0,a[1]);
else
a[1]>a[n]?printf("%d %d %d",a[1],(a[n/2]+a[n/2+1])/2,a[n]):printf("%d %d %d",a[n],(a[n/2]+a[n/2+1])/2,a[1]);//可能出现两数相等的情况
}
else
a[1]>a[n]?printf("%d %d %d",a[1],a[(n+1)/2],a[n]):printf("%d %d %d",a[n],a[(n+1)/2],a[1]);
return 0;
}
注意:当数的个数为偶数时,求中间两数的平均数时,可能出现两数相等的情况