题目链接->link
思路
- 将各位求和后的结果存入整形数组con[]中,然后根据con[]的值输出对应的拼音。
代码
#include <stdio.h>
#include <math.h>
#include <string.h>
#include <iostream>
using namespace std;
char str[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};//存储数字对应的拼音
int main(){
char n[105];
scanf("%s",n);
int sum=0;
for(int i=0;i<strlen(n);i++){
sum+=n[i]-'0';
}
int con[10],num=0;
while(sum!=0){//将sum从低位到高位存储到con[]中,1230->0123
con[num++]=sum%10;
sum/=10;
}
for(int i=num-1;i>=0;i--){//将con[]从高位到低位输出
printf("%s",str[con[i]]);
if(i!=0)printf(" ");
}
return 0;
}