有一堆数据:String bom = "AAAA=1,BBBBB=2,CCCC=3,AAAA=1,BBBBB=2,CCCC=312134";
需要取得的结果为去重复的key,把Value值相加:{AAAA=3, BBBBB=6, CCCC=312140}
第一种方法:(老大写的) 效率高.简单.等.
package wsc.com.it.repeatString;
import java.util.LinkedHashMap;
import java.util.Map;
public class BomString {
public static void main(String[] args) {
String bom = "AAAA=1,BBBBB=2,CCCC=3,AAAA=1,BBBBB=2,CCCC=312134";
bom = processBom(bom);
System.out.println(bom);
}
private static String processBom(String bom) {
if (bom == null) {
return null;
}
String bomData = null;
String[] srcBom = bom.trim().split(",");
Map<String , Long> bomMap = new LinkedHashMap<String, Long>(0);
//去掉重复的Key 取得Value值
for (int i = 0; i < srcBom.length; i++) {String bom1 = srcBom[i];
String[] bomTemp = bom1.split("=");
String key = bomTemp[0].trim();
Long totle = Long.parseLong(bomTemp[1].trim().toString());
if (bomMap.get(key)==null) {
bomMap.put(key, totle);
}
bomMap.put(key, Long.parseLong(bomMap.get(key).toString())+totle);
}
bomData = bomMap.toString().replace("\\{","").replace("\\}", "");
return bomData;
}
}
第二种方法(自己写的);效率低.循环多.代码复杂 .但功能是实现了的..呵呵..待发.....