#!/bin/python3
import math
import os
import random
import re
import sys
# Complete the isValid function below.
def isValid(s):
zd={}
for c in s:
if c not in zd.keys():
zd[c]=1
else:
zd[c]+=1
a=list(zd.values())
if len(set(a))==1: #所有字母的次数相同
result='YES'
elif len(set(a))==2 and (a.count(max(a))==1) and (max(a)-min(a)==1):
#存在一个字母出现的次数比其他的多1
result='YES'
elif len(set(a))==2 and (min(a)==1) and (a.count(min(a))==1):
#其他字母的次数相同(>=2),有一个字母只出现1次
result='YES'
else:
result='NO'
return result
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
s = input()
result = isValid(s)
fptr.write(result + '\n')
fptr.close()
String ManipulationSherlock and the Valid String
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转载自blog.csdn.net/weixin_45405128/article/details/104204767
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