资料:https://blog.csdn.net/weixin_37536446/article/details/82109431
分组函数自定义:
x = {'o':[1,1,1,2,2,2,3,3,3],'q':[1,2,3,4,5,7,8,8,10],'w':[1,2,3,12,6,5,6,7,9]}
x = pd.DataFrame(x)
# x.map(type_map)
def number(x):
zz = x[x>4].count()
return zz
q = x.groupby('o')['q'].agg({'tuo':number}).reset_index()
q