LETCODE 1108 INVALID_ID

代码简单,按照题目要求做就行了
public:
string defangIPaddr(string address)
{
vectortemp;
string c;
for (int i = 0; i < address.size(); i++)
{
if (address[i] != ‘.’)
{
temp.push_back(address[i]);
}
else
{
temp.push_back(’[’);
temp.push_back(’.’);
temp.push_back(’]’);
}
}
for (auto p : temp)
{
c.push_back§;
++p;
}
return c;
}
};

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转载自blog.csdn.net/qq_40742888/article/details/97620347