<?php
$json = '{"state":"1","info":"登录成功"}';
$arr = (array) json_decode($json,true);
echo '状态码:'. $arr['state'];
$json2 = '{"data":{"date":"2019-02-09","team":"第二学期"}}';
$arr2 = (array) json_decode($json,true);
echo '日期:'. $arr2['data']['date'].'学期:'.$arr2['data']['team'];
?>
PHP——取JSON属性值demo
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转载自blog.csdn.net/qq_17497931/article/details/87733372
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