难度:简单
一、题目描述:
二、解题分析:
1、剑指解析
2、代码实现
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def kthLargest(self, root: TreeNode, k: int) -> int:
if not root: return
stack = []
res = []
while root or stack:
while root:
stack.append(root)
root = root.right
root = stack.pop()
res.append(root.val)
if len(res)==k: return res[-1]
root = root.left
return