#include<iostream>
#include<cmath>
using namespace std;
unsigned fun(unsigned integ)
{
int b,count=0;
b=integ;
while(integ!=0)
{
integ=integ/10;
count++;
}
cout<<round(b/pow(10,count-2))-10*(round(b/pow(10,count-1)));
}
int main()
{
unsigned n=0;
cin>>n;
fun(n);
}
输出一个大于10的无符号n位整形的n-1位
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转载自blog.csdn.net/huangziguang/article/details/104628763
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