//双击退出事件
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if(keyCode == KeyEvent.KEYCODE_BACK){
ExitApp(); //调用双击退出函数
}
return false;
}
private long exitTime = 0;
public void ExitApp() {
if ((System.currentTimeMillis() - exitTime) > 2000){
Snackbar.make(lstData, "再按一次退出程序", Snackbar.LENGTH_LONG).setAction("Action", null).show();
exitTime = System.currentTimeMillis();
} else {
finish();
System.exit(0);
}
}
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转载自www.cnblogs.com/good-study/p/9072218.html
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