patB1049/patA1104 数列的片段和


#include <iostream>

#include <cstdio>
using namespace std;
const int maxn=100010;
double S[maxn];
int main(int argc, char** argv) {
int N;
scanf("%d",&N);
for(int i=1;i<=N;i++) scanf("%lf",&S[i]);
double ans=0;
for(int i=1;i<=N;i++) ans+=S[i]*i*(N+1-i);
printf("%0.2f",ans);
return 0;
}

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转载自blog.csdn.net/qq_37816373/article/details/80328900