1082 Read Number in Chinese (25分)
Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu
first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
. Note: zero (ling
) must be handled correctly according to the Chinese tradition. For example, 100800 is yi Shi Wan ling ba Bai
.
Input Specification:
Each input file contains one test case, which gives an integer with no more than 9 digits.
Output Specification:
For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.
Sample Input 1:
-123456789
Sample Output 1:
Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
Sample Input 2:
100800
Sample Output 2:
yi Shi Wan ling ba Bai
解题思路:
因为本身位数不会太长,因此我们可以将整个数字分段处理,每四个位一组。
#include<iostream>
#include<string>
using namespace std;
string num[10] = { "ling","yi","er","san","si","wu","liu","qi","ba","jiu" };
string wei[5] = { "Shi","Bai","Qian","Wan","Yi" };
int main()
{
string str;
cin >> str;
int len = str.length();
int left = 0;
int right = len - 1;
if(str[0] == '-')
{
cout<<"Fu";
left++;
}
while (left + 4 <= right)
{
right -= 4;
}
while (left < len)
{
bool flag = false; //记录有没有积累的0
bool isPrint = false; //isPrint == false 表示当前部分没有输出过其中的位
while (left <= right)
{
if (left > 0 && str[left] == '0')
flag = true;
else //如果当前位不是0
{
if(flag == true)
{
cout << " ling";
flag = false;
}
//只要不是首位(包括负号),后面的每一位前都输出空格
if (left > 0)cout << " ";
cout << num[str[left] - '0'];
isPrint = true;
if (left != right)
cout << " " << wei[right - left - 1];
}
left++;
}
if (isPrint == true && right != len - 1) //只要不是个位输出万亿
{
cout << " " << wei[(len - 1 - right)/4 + 2];
}
right += 4;
}
return 0;
}