1082 Read Number in Chinese (25)(25 分)
Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output “Fu” first if it is negative. For example, -123456789 is read as “Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu”. Note: zero (“ling”) must be handled correctly according to the Chinese tradition. For example, 100800 is “yi Shi Wan ling ba Bai”.
Input Specification:
Each input file contains one test case, which gives an integer with no more than 9 digits.
Output Specification:
For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.
Sample Input 1:
-123456789
Sample Output 1:
Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
Sample Input 2:
100800
Sample Output 2:
yi Shi Wan ling ba Bai
题目大意:按中文发音规则输出一个绝对值在9位以内的整数。
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
char num[10][5] = {
"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"
};
char wei[5][5] = {"Shi", "Bai", "Qian", "Wan", "Yi"};
int main() {
char str[15];
scanf("%s", str);
int len = strlen(str);
int left = 0, right = len - 1;
if(str[0] == '-') {
printf("Fu");
left++;
}
while(left + 4 <= right) {
right -= 4;
}
while(left < len) {
bool flag = false;
bool isPrint = false;
while(left <= right) {
if(left > 0 && str[left] == '0') {
flag = true;
} else {
if(flag) {
printf(" ling");
flag = false;
}
if(left > 0) {
printf(" ");
}
printf("%s", num[str[left] - '0']);
isPrint = true;
if(left != right) {
printf(" %s", wei[right - left - 1]);
}
}
left++;
}
if(isPrint && right != len - 1) {
printf(" %s", wei[(len - 1 - right) / 4 + 2]);
}
right += 4;
}
return 0;
}