题目:
分析:
直接变成了2维的列表
t=[i.split(",") for i in transactions]
python代码:
class Solution:
def invalidTransactions(self, transactions: List[str]) -> List[str]:
t=[i.split(",") for i in transactions]
A=[]
#是否大于1000
for i in range(0,len(t)):
if int(t[i][2])>1000:
w=t[i][0]+','+t[i][1]+','+t[i][2]+','+t[i][3]
A.append(w)
continue
for j in range(0,len(t)):
if i==j:
continue
if t[i][0]!=t[j][0]:
continue
if t[i][3]==t[j][3]:
continue
if abs(int(t[i][1])-int(t[j][1]))<=60:
w=t[i][0]+','+t[i][1]+','+t[i][2]+','+t[i][3]
A.append(w)
break
return A