5位运动员参加了10米台跳水比赛,有人让他们预测比赛结果
A选手说:B第二,我第三;
B选手说:我第二,E第四;
C选手说:我第一,D第二;
D选手说:C最后,我第三;
E选手说:我第四,A第一;
比赛结束后,每位选手都说对了一半,请编程确定比赛的名次。
# include <stdio.h>
# include <windows.h>
int main()
{
int a = 0;
int b = 0;
int c = 0;
int d = 0;
int e = 0;
for (a = 1; a <= 5; ++a)
for (b = 1; b <= 5; ++b)
for (c = 1; c <= 5; ++c)
for (d = 1; d <= 5; ++d)
for (e = 1; e <= 5; ++e)
{
if (
((b == 2) + (a == 3) == 1) &&
((b == 2) + (e == 4) == 1) &&
((c == 1) + (d == 2) == 1) &&
((c == 5) + (d == 3) == 1) &&
((e == 4) + (a == 1) == 1)
)
{
//如果a原来的值为3,将1左移两位得到对应的
//值与原来的flag按位或,并将结果赋给flag,
//最终五次下来,如果每次1移动的位数不一样
//,则最终的结果应是低五位全为1
int flag = 0;
flag |= (1 << (a - 1));
flag |= (1 << (b - 1));
flag |= (1 << (c - 1));
flag |= (1 << (d - 1));
flag |= (1 << (e - 1));
if (flag == 31) //如果低五位全为1,flag值为2^5 -1 == 31
{
printf("a是第%d名,\
b是第%d名,\
c是第%d名,\
d是第%d名,\
e是第%d名\n",\
a, b, c, d, e); //‘\’为续行符
}
}
system("pause");
return 0;
}