#include <stdio.h>
double mypow( double x, int n );
int main()
{
double x;
int n;
scanf("%lf %d", &x, &n);
printf("%f\n", mypow(x, n));
return 0;
}
double mypow( double x, int n )
{
double c = 1;
for(int i = 1; i <= n; i++)
{
c = x * c;
}
return c;
}
(PAT)实现一个计算x n (n≥0)的函数。
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转载自blog.csdn.net/qq_52001969/article/details/111437766
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