(PAT)实现一个计算x n (n≥0)的函数。

#include <stdio.h>

double mypow( double x, int n );

int main()
{
    
    
    double x;
    int n;

    scanf("%lf %d", &x, &n);
    printf("%f\n", mypow(x, n));

    return 0;
}

double mypow( double x, int n )
{
    
    
    double c = 1;
    for(int i = 1; i <= n; i++)
    {
    
    
         c = x * c;
    }
    return c;
}

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转载自blog.csdn.net/qq_52001969/article/details/111437766
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