中微作业公式

Before:

M = p 1 x 1 + p 2 x 2 M=p_1x_1+p_2x_2 M=p1x1+p2x2
U ( x 1 , x 2 ) = x 1 x 2 U(x_1,x_2)=x_1x_2 U(x1,x2)=x1x2
10 = x 1 + x 2 10 = x_1+x_2 10=x1+x2
d ( u ( x 1 , x 2 ) d ( x 1 ) d ( u ( x 1 , x 2 ) d ( x 2 ) = x 2 x 1 = p 1 p 2 = 1 \frac{\frac{d(u(x_1,x_2)}{d(x_1)}} {\frac{d(u(x_1,x_2)}{d(x_2)}} =\frac{x_2}{x_1} =\frac{ p_1}{p_2} =1 d(x2)d(u(x1,x2)d(x1)d(u(x1,x2)=x1x2=p2p1=1
so : x 1 = 5 ; x 2 = 5 x_1 = 5;x_2=5 x1=5;x2=5

T U = 25 TU = 25 TU=25

After:

M = p 1 x 1 + p 2 x 2 M=p_1x_1+p_2x_2 M=p1x1+p2x2
U ( x 1 , x 2 ) = x 1 x 2 U(x_1,x_2)=x_1x_2 U(x1,x2)=x1x2
10 = 2.5 x 1 + x 2 10 = 2.5x_1+x_2 10=2.5x1+x2
d ( u ( x 1 , x 2 ) d ( x 1 ) d ( u ( x 1 , x 2 ) d ( x 2 ) = x 2 x 1 = p 1 p 2 = 2.5 \frac{\frac{d(u(x_1,x_2)}{d(x_1)}} {\frac{d(u(x_1,x_2)}{d(x_2)}} =\frac{x_2}{x_1} =\frac{ p_1}{p_2} =2.5 d(x2)d(u(x1,x2)d(x1)d(u(x1,x2)=x1x2=p2p1=2.5
so : x 1 ′ = 2 ; x 2 ′ = 5 x_1' = 2;x_2'=5 x1=2;x2=5
T U = 10 TU = 10 TU=10

TE:

T E = x 1 ′ − x 1 = − 3 TE = x_1' - x_1 =-3 TE=x1x1=3

SE:

U = 25 = x 1 x 2 U =25 =x_1x_2 U=25=x1x2
d ( u ( x 1 , x 2 ) d ( x 1 ) d ( u ( x 1 , x 2 ) d ( x 2 ) = x 2 x 1 = p 1 p 2 = 2.5 \frac{\frac{d(u(x_1,x_2)}{d(x_1)}} {\frac{d(u(x_1,x_2)}{d(x_2)}} =\frac{x_2}{x_1} =\frac{ p_1}{p_2} =2.5 d(x2)d(u(x1,x2)d(x1)d(u(x1,x2)=x1x2=p2p1=2.5
x 1 ′ ′ = 10 ; x 2 ′ ′ = 2.5 10 x_1'' = \sqrt{10};x_2''=2.5\sqrt{10} x1=10 ;x2=2.510
S E = x 1 ′ ′ − x 1 = − ( 5 − 10 ) SE =x_1''-x_1= -(5 - \sqrt{10}) SE=x1x1=(510 )

EE:

E E = T E − S E = − ( 10 − 2 ) EE = TE-SE = -(\sqrt{10} - 2) EE=TESE=(10 2)

the budget line

c 1 p 1 + ( 1 + π 1 + i ) c 2 p 2 = m 1 + m 2 1 1 + i c_1p_1+(\frac{1+\pi}{1+i})c_2p_2=m_1+m_2\frac{1}{1+i} c1p1+(1+i1+π)c2p2=m1+m21+i1

c 1 + ( 1 + 5 % 1 + 5 % ) c 2 = 100 + 100 ( 1 1 + 5 % ) c_1 + (\frac{1+5\%}{1+5\%})c_2=100+100(\frac{1}{1+5\%}) c1+(1+5%1+5%)c2=100+100(1+5%1)

c 1 = 195.238 − c 2 c_1 = 195.238-c_2 c1=195.238c2

A

d ( u A ) / d ( c 1 ) = ( 1 / 3 ) c 1 ( − 2 / 3 ) c 2 2 / 3 d(u_A)/d(c_1) = (1/3) c_1^{(-2/3)}c_2^{2/3} d(uA)/d(c1)=(1/3)c1(2/3)c22/3

d ( u A ) / d ( c 2 ) = ( 2 / 3 ) c 1 ( 1 / 3 ) c 2 − 1 / 3 d(u_A)/d(c_2) = (2/3) c_1^{(1/3)}c_2^{-1/3} d(uA)/d(c2)=(2/3)c1(1/3)c21/3

d ( u A ) / d ( c 1 ) d ( u A ) / d ( c 2 ) = ( 1 / 2 ) c 2 c 1 = 1 \frac{d(u_A)/d(c_1)}{d(u_A)/d(c_2)} = (1/2)\frac{c_2}{c_1} = 1 d(uA)/d(c2)d(uA)/d(c1)=(1/2)c1c2=1

so :
c 2 = 2 c 1 c_2=2c_1 c2=2c1
c 1 = 195.238 − c 2 c_1 = 195.238-c_2 c1=195.238c2
c 1 = 65.079 c_1 = 65.079 c1=65.079
c 2 = 130.158 c_2=130.158 c2=130.158
u a = 103.306 u_a =103.306 ua=103.306
saver

B

d ( u B ) / d ( c 1 ) = ( 2 / 3 ) c 1 ( − 1 / 3 ) c 2 1 / 3 d(u_B)/d(c_1) = (2/3) c_1^{(-1/3)}c_2^{1/3} d(uB)/d(c1)=(2/3)c1(1/3)c21/3

d ( u B ) / d ( c 2 ) = ( 1 / 3 ) c 1 ( 2 / 3 ) c 2 − 2 / 3 d(u_B)/d(c_2) = (1/3) c_1^{(2/3)}c_2^{-2/3} d(uB)/d(c2)=(1/3)c1(2/3)c22/3

d ( u B ) / d ( c 1 ) d ( u B ) / d ( c 2 ) = 2 c 2 c 1 = 1 \frac{d(u_B)/d(c_1)}{d(u_B)/d(c_2)} = 2 \frac{c_2}{c_1} = 1 d(uB)/d(c2)d(uB)/d(c1)=2c1c2=1
so :
c 2 = 1 / 2 c 1 c_2 = 1/2 c_1 c2=1/2c1
c 1 = 195.238 − c 2 c_1 = 195.238-c_2 c1=195.238c2
c 1 = 130.15867 c_1 = 130.15867 c1=130.15867
c 2 = 65.079 c_2=65.079 c2=65.079
u b = 103.306 u_b =103.306 ub=103.306
borrower

s a v e r a saver_a savera

s a v e r A = m 1 − c 1 ∗ = m 1 − ( m 1 + m 2 1 1 + i ) / ( 1 + 2 ( 1 + π 1 + i ) ) = 100 − ( 100 + 100 1 1 + i ) / ( 1 + 2 ( 1 + 0.05 1 + i ) ) saver_A=m_1-c_1^*=m_1-(m_1+m_2\frac{1}{1+i})/(1+2(\frac{1+\pi}{1+i}))=100-(100+100\frac{1}{1+i})/(1+2(\frac{1+0.05}{1+i})) saverA=m1c1=m1(m1+m21+i1)/(1+2(1+i1+π))=100(100+1001+i1)/(1+2(1+i1+0.05))

s a v e r b saver_b saverb

s a v e r B = m 1 − c 1 ∗ = m 1 − ( m 1 + m 2 1 1 + i ) / ( 1 + ( 1 / 2 ) ( 1 + π 1 + i ) ) = 100 − ( 100 + 100 1 1 + i ) / ( 1 + ( 1 / 2 ) ( 1 + 0.05 1 + i ) ) saver_B=m_1-c_1^*=m_1-(m_1+m_2\frac{1}{1+i})/(1+(1/2)(\frac{1+\pi}{1+i}))=100-(100+100\frac{1}{1+i})/(1+(1/2)(\frac{1+0.05}{1+i})) saverB=m1c1=m1(m1+m21+i1)/(1+(1/2)(1+i1+π))=100(100+1001+i1)/(1+(1/2)(1+i1+0.05))

s a v e r a + s a v e r b saver_a+saver_b savera+saverb

s a v e a l l = s a v e r a + s a v e r b = 100 − ( 100 + 100 1 1 + i ) / ( 1 + 2 ( 1 + 0.05 1 + i ) ) + 100 − ( 100 + 100 1 1 + i ) / ( 1 + ( 1 / 2 ) ( 1 + 0.05 1 + i ) ) save_{all} =saver_a+saver_b=100-(100+100\frac{1}{1+i})/(1+2(\frac{1+0.05}{1+i}))+100-(100+100\frac{1}{1+i})/(1+(1/2)(\frac{1+0.05}{1+i})) saveall=savera+saverb=100(100+1001+i1)/(1+2(1+i1+0.05))+100(100+1001+i1)/(1+(1/2)(1+i1+0.05))

interesting rate raise up to 10%

c 1 p 1 + ( 1 + π 1 + i ) c 2 p 2 = m 1 + m 2 1 1 + i c_1p_1+(\frac{1+\pi}{1+i})c_2p_2=m_1+m_2\frac{1}{1+i} c1p1+(1+i1+π)c2p2=m1+m21+i1

c 1 + ( 1 + 5 % 1 + 10 % ) c 2 = 100 + 100 ( 1 1 + 10 % ) c_1 + (\frac{1+5\%}{1+10\%})c_2=100+100(\frac{1}{1+10\%}) c1+(1+10%1+5%)c2=100+100(1+10%1)

c 1 = 190.909 − 0.95454545 c 2 c_1 = 190.909-0.95454545c_2 c1=190.9090.95454545c2

A after raising

c 1 = 190.909 − 0.95454545 c 2 c_1 = 190.909-0.95454545c_2 c1=190.9090.95454545c2
c 2 = 2 ∗ 0.954545 c 1 c_2=2*0.954545c_1 c2=20.954545c1
c 1 = 63.64 c_1 = 63.64 c1=63.64
c 2 = 133.33 c_2 = 133.33 c2=133.33
u a = 104.1986 u_a = 104.1986 ua=104.1986
better

B after raising

c 1 = 190.909 − 0.95454545 c 2 c_1 = 190.909-0.95454545c_2 c1=190.9090.95454545c2
c 2 = 1 / 2 ∗ 0.954545 c 1 c_2=1/2*0.954545c_1 c2=1/20.954545c1
c 1 = 127.27 c_1 = 127.27 c1=127.27
c 2 = 66.67 c_2 = 66.67 c2=66.67
u b = 102.5956 u_b = 102.5956 ub=102.5956
worse

A

M U c = 40 c 3 s MU_c=40c^3s MUc=40c3s
M U s = 10 c 4 MU_s=10c^4 MUs=10c4
M R S = M U c M U s = 40 c 3 s 10 c 4 = 4 s c = p c p s = 32 ; s = 8 c MRS=\frac {MU_c}{MU_s}=\frac{40c^3s}{10c^4}=\frac{4s}{c}=\frac{p_c}{p_s}=32;s=8c MRS=MUsMUc=10c440c3s=c4s=pspc=32;s=8c

budget line: 32 c + 1 s = 80 32c+1s=80 32c+1s=80

so : c = 2 ; s = 16 c = 2 ; s=16 c=2;s=16

and utlity = 2560

B

M R S = M U c M U s = 40 c 3 s 10 c 4 = 4 s c = p c p s = 16 ; s = 4 c MRS=\frac {MU_c}{MU_s}=\frac{40c^3s}{10c^4}=\frac{4s}{c}=\frac{p_c}{p_s}=16;s=4c MRS=MUsMUc=10c440c3s=c4s=pspc=16;s=4c

budget line: 16 c + 1 s = 80 16c+1s=80 16c+1s=80

so c = 4 ; s = 16 c =4;s=16 c=4;s=16

and utlity = 40960

c

M R S = M U c M U s = 40 c 3 s 10 c 4 = 4 s c = p c p s = 16 ; s = 4 c MRS=\frac {MU_c}{MU_s}=\frac{40c^3s}{10c^4}=\frac{4s}{c}=\frac{p_c}{p_s}=16;s=4c MRS=MUsMUc=10c440c3s=c4s=pspc=16;s=4c

and utlity = 2560

c = 64 0 ( 1 / 5 ) ; s = 4 ( 64 0 ( 1 / 5 ) ) ; M b = 16 c + 1 s = 72.822568121 c = 640^{(1/5)};s=4( 640^{(1/5)});M_b = 16c+1s=72.822568121 c=640(1/5);s=4(640(1/5));Mb=16c+1s=72.822568121

S E = 64 0 ( 1 / 5 ) − 2 SE = 640^{(1/5)}-2 SE=640(1/5)2

E E = 4 − 64 0 ( 1 / 5 ) EE = 4-640^{(1/5)} EE=4640(1/5)

1 3 3000 + 1 3 2000 + 1 3 1000 = 2000 \frac{1}{3}3000+\frac{1}{3}2000+\frac{1}{3}1000=2000 313000+312000+311000=2000
he is willing to pay 2000 for a car.type B

0 ∗ 3000 + 1 2 2000 + 1 2 1000 = 1500 0*3000+\frac{1}{2}2000+\frac{1}{2}1000=1500 03000+212000+211000=1500
he is willing to pay 1500 for a car.type C

0.6 ∗ 1000000 + 0.2 ∗ 1000000 + 0.1 ∗ 1000000 = 900000 0.6*1000000+0.2*1000000+0.1*1000000=900000 0.61000000+0.21000000+0.11000000=900000

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转载自blog.csdn.net/qq_42830971/article/details/110132855