bfs:迷宫问题

从迷宫开始的s点走到t点,其中*代表墙壁,.代表平地。

#include <iostream>
#include <cstdio>
#include <string>
#include <algorithm>
#include <cmath>
#include <iomanip>
#include <vector>
#include <map>
#include <queue>
using namespace std;
const int maxn = 100;
struct Node{
    
    
    int x,y;
    int step;
};
Node start,end,temp;
int n,m;
char maze[maxn][maxn];
bool flag[maxn][maxn];
int mx[4]={
    
    0,0,1,-1};
int my[4]={
    
    1,-1,0,0};
bool Is_push(int x,int y)
{
    
    
    if(x>=n||x<0||y>=m||y<0) return false;
    if(flag[x][y] == true) return false;
    if(maze[x][y] == '*') return false;
    return true;
}
void bfs()
{
    
    
    int i;
    queue<Node>q;
    q.push(start);
    flag[start.x][start.y] = true;
    while(!q.empty())
    {
    
    
        temp = q.front();
        if(temp.x == end.x&&temp.y == end.y)
            return;
        int layer = temp.step;
        q.pop();
        for(i=0;i<4;i++)
        {
    
    
           int newx = temp.x+mx[i];
           int newy = temp.y+my[i];
           if(Is_push(newx,newy))
           {
    
    
               Node n;
               n.x = newx;
               n.y = newy;
               n.step = layer+1;
               q.push(n);
               flag[newx][newy] = true;
           }
        }
    }
}
int main()
{
    
    
    cin>>n>>m;
    int i,j;
    for(i = 0;i < n;i++)
    {
    
    
        getchar();
        for(j = 0;j < m; j++)
        {
    
    
            maze[i][j] = getchar();
        }
    }
    cin>>start.x>>start.y>>end.x>>end.y;
    start.step = 0;
    bfs();
    cout<<temp.step<<endl;
}

测试案例:
5 5

...
.S.
.**.
…T

输出:11

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转载自blog.csdn.net/weixin_44142774/article/details/113276424