B1002_写出这个数 (20分)

读入一个正整数 n，计算其各位数字之和，用汉语拼音写出和的每一位数字。
输入格式：
每个测试输入包含 1 个测试用例，即给出自然数 n 的值。这里保证 n 小于 10^100
输出格式：
在一行内输出 n 的各位数字之和的每一位，拼音数字间有 1 空格，但一行中最后一个拼音数字后没有空格。

输入样例：
1234567890987654321123456789
输出样例：
yi san wu

第一种方法：栈

#include<string>
#include<stack>
#include<iostream>
using namespace std;

int main() {
    
    
	int sum = 0;
	string s;
	cin >> s;
	
	for (unsigned int i = 0; i < s.length(); i++) {
    
    
		sum += s[i] - '0';
	}

	stack<string> PinYin;
	
	while (sum) {
    
    
		int digit = sum % 10;
		switch(digit) {
    
    
			case 0: PinYin.push("ling");break;
			case 1: PinYin.push("yi");break;
			case 2: PinYin.push("er");break;
			case 3: PinYin.push("san");break;
			case 4: PinYin.push("si");break;
			case 5: PinYin.push("wu");break;
			case 6: PinYin.push("liu");break;
			case 7: PinYin.push("qi");break;
			case 8: PinYin.push("ba");break;
			case 9: PinYin.push("jiu");break;
			default: break; 
		}
		sum /= 10;
	}
	
	for (unsigned int i = 0; i <= PinYin.size() + 1; i++) {
    
    
		if (i == PinYin.size() + 1) {
    
    
			cout << PinYin.top();
		} else {
    
    
			cout << PinYin.top() << " ";
		}
		PinYin.pop();
	}
	
	return 0;
} 

第二种方法：二维字符数组

#include<cstdio>
#include<cstring>

int main() {
    
    
	char qtc[110];
	gets(qtc);
	int len = strlen(qtc);
	int sum = 0;

	for (int i = 0; i < len; i++) {
    
    
		sum += qtc[i] - '0'; // 将字符转化为数字并累加 
	}
	
	int num = 0, ans[10];
	while (sum) {
    
    
		ans[num++] = sum % 10;  // 将 sum中的每一位保存在数组中 
		sum /= 10;
	}
	
	char PinYin[10][5] = {
    
    "ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"};
	for (int i = num - 1; i >= 0; i--) {
    
    
		printf("%s", PinYin[ans[i]]);  // ans[i]即为高位开始的第i个数字
		if (i) printf(" ");  // i不为0则空格隔开
		else printf("\n");	 
	}
	
	return 0;
} 

第三种方法： switch case

#include<stdio.h>
#include<string.h>

int main() {
    
    
	
	int sum = 0;
    char ch;
    ch = getchar();
    while (ch != '\n')
    {
    
    
        switch (ch)
        {
    
    
        case '1':
            sum += 1;
            break;
        case '2':
            sum += 2;
            break;
        case '3':
            sum += 3;
            break;
        case '4':
            sum += 4;
            break;
        case '5':
            sum += 5;
            break;
        case '6':
            sum += 6;
            break;
        case '7':
            sum += 7;
            break;
        case '8':
            sum += 8;
            break;
        case '9':
            sum += 9;
            break;
        default:
            sum += 0;
            break;
        }
        ch = getchar(); //是继续往下读字符啦
    }

    char *result[100];
    int digit_count = 0;
    while(sum != 0)
    {
    
    
        int digit = sum % 10;
        switch (digit)
        {
    
    
        case 0:
            result[digit_count] = "ling";
            break;
        case 1:
            result[digit_count] = "yi";
            break;
        case 2:
            result[digit_count] = "er";
            break;
        case 3:
            result[digit_count] = "san";
            break;
        case 4:
            result[digit_count] = "si";
            break;
        case 5:
            result[digit_count] = "wu";
            break;
        case 6:
            result[digit_count] = "liu";
            break;
        case 7:
            result[digit_count] = "qi";
            break;
        case 8:
            result[digit_count] = "ba";
            break;
        case 9:
            result[digit_count] = "jiu";
            break;
        default:
            break;
        }
        sum = sum / 10;
        digit_count++;
    }
 	
 	for (int i = digit_count - 1; i >= 0; i--) {
    
    
 		if (i == 0) {
    
    
 			printf("%s", result[i]);
		 } else {
    
    
		 	printf("%s ", result[i]);
		 }
	 }

    return 0;
}