案例描述:
设计一个英雄的结构体,包括成员姓名,年龄,性别;创建结构体数组,数组中存放5名英雄。
通过冒泡排序的算法,将数组中的英雄按照年龄进行升序排序,最终打印排序后的结果。
{“刘备”,23,“男”},
{“关羽”,22,“男”},
{“张飞”,20,“男”},
{“赵云”,21,“男”},
{“貂蝉”,19,“女”},
#include <iostream>
#include<string>
using namespace std;
struct hero
{
string name;
int age;
string sex;
};
void maopao(hero arry[], int len) {
for (int i = 0; i < len - 1; i++) {
for (int j = 0; j < len - i - 1; j++) {
if (arry[j].age > arry[j + 1].age) {
hero temp = arry[j + 1];
arry[j + 1] = arry[j];
arry[j] = temp;
}
}
}
}
void printf(hero arry[], int len) {
for (int i = 0; i < len - 1; i++) {
cout << arry[i].name << "的年龄是" << arry[i].age << ",性别是" << arry[i].sex << endl;
}
}
int main() {
//1.定义英雄
hero arry[5] = {
{
"刘备",23,"男"},
{
"关羽",22,"男"},
{
"张飞",20,"男"},
{
"赵云",21,"男"},
{
"貂蝉",19,"女"},
};
//2.数组长度
int len = sizeof(arry) / sizeof(arry[0]);
//3.使用冒泡排序,按照年龄升序排列
maopao(arry, len);
//4.打印输出
printf(arry, len);
}