JS获取url请求参数,代码如下:

	// 获取url请求参数
function getQueryParams() {
    var query = location.search.substring(1)
    var arr = query.split('&')
    var params = {}
    for (var i = 0; i < arr.length; i++) {
        var pair = arr[i].split('=')
        params[pair[0]] = pair[1]
    }
    console.log(params)
    return params
}

function getQueryParam(key) {
    var query = location.search.substring(1)
    var arr = query.split('&')
    for (var i = 0; i < arr.length; i++) {
        var pair = arr[i].split('=')
        if (pair[0] == key) {
            return pair[1]
        }
    }
    return undefined
}

1.location.search是url中问号及之后的字符串,如'?a=1&b=2',location.search.substring(1)即是去掉了问号,如'a=1&b=2'

2.getQueryParams()返回的是对象,如:

 {a: "1", b: "1"}

3.getQueryParam(key)返回的是key对应的value值。

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转载自blog.csdn.net/chenrui310/article/details/129415775