js获取url请求参数

function getQueryString(name)
{
  var reg = new RegExp("(^|&)"+ name +"=([^&]*)(&|$)");
  var r = decodeURI(window.location.search).substr(1).match(reg);
  if(r!=null)return  unescape(r[2]); return null;
}

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转载自blog.csdn.net/weixin_37704921/article/details/82967929