Power Mouth
Time Limit: 2000/1000ms (Java/Others)
Problem Description:
Your task is to calculate the sum of some integers.
Output:
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.
Sample Input:
It is easy.
Sample Output:
It is simple.
解题思路:题目很简单,输出之间要有一空行。
AC代码:
1 #include<bits/stdc++.h>
2 using namespace std;
3 typedef long long LL;
4 LL sum,n,m,x;bool flag;
5 int main(){
6 while(cin>>n){
7 flag=false;
8 while(n--){
9 cin>>m;sum=0;
10 if(flag)cout<<endl;//输出之间留一空行,第一次不输出,以后每次都输出空行
11 while(m--){cin>>x;sum+=x;}
12 cout<<sum<<endl;
13 flag=true;
14 }
15 }
16 return 0;
17 }