题目链接:http://acm.zcmu.edu.cn/JudgeOnline/problem.php?id=1508
【分析】就是二分法,构造一个函数实现
#include<bits/stdc++.h>
using namespace std;
int a[100010];
void find(int x,int n)
{
int st=0,ed=n,mid;
while(st<ed)
{
mid=(st+ed)/2;
if(x==a[mid])
{
printf("%d found at %d\n",x,mid+1);
return ;
}
else if(x<a[mid])
ed=mid;
else if(x>a[mid])
st=mid+1;
}
printf("%d not found\n",x);
}
int main()
{
int n,m;
memset(a,0,sizeof(a));
scanf("%d%d",&n,&m);
for(int i=0;i<n;i++)
scanf("%d",&a[i]);
for(int i=0;i<m;i++)
{
int x;
scanf("%d",&x);
find(x,n);
}
return 0;
}