Codeforce735D(哥德巴赫猜想)

总结:

题意:

将一个数(N>=2)最少分成多少个素数?

代码:

#include<iostream>
#include<algorithm>
#include<cstdio>
#include<string>
#include<string.h>
#include<map>
#include<queue>
#include<cmath>
#include<vector>
using namespace std;
typedef long long ll;
bool isprime(ll x){
  ll mid=sqrt(x);
  for(int i=2;i<=mid;i++){
    if(x%i==0)return false;
  }
  return true;
}
int main(){
  ll n;
  while(~scanf("%lld",&n)){;
     if(n&1){
       if(isprime(n))cout<<1<<endl;
       else if(isprime(n-2))cout<<2<<endl;
       else cout<<3<<endl;
     }else{
       if(n==2)cout<<1<<endl;
       else cout<<2<<endl;
   }
  }
  return 0;
}

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转载自blog.csdn.net/zxk_hi/article/details/80811677