版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/fyq201749/article/details/82191762
tf.assert_rank_in() 判断x的秩是否在ranks之间,如果不是抛出异常
参数:
tf.assert_rank_in(
x,
ranks,
data=None,
summarize=None,
message=None,
name=None
)
使用案例:
import tensorflow as tf
import numpy as np
x = [[1, 2, 3], [4, 5, 6]]
sess = tf.Session()
with tf.control_dependencies([tf.assert_rank_in(x=x, rank=(2, 4))]):
output = tf.reduce_sum(x)
print(sess.run(output))