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tf.assert_none_equal()x和y中的元素如果有相等的就抛出异常
参数:
tf.assert_none_equal(
x,
y,
data=None,
summarize=None,
message=None,
name=None
)
使用案例:
import tensorflow as tf
x = [1, 2]
y = [4, 3]
sess = tf.Session()
with tf.control_dependencies([tf.assert_none_equal(x, y)]):
output = tf.reduce_sum(x)
print(sess.run(output))