题目描述
获取员工其当前的薪水比其manager当前薪水还高的相关信息,当前表示to_date='9999-01-01',
结果第一列给出员工的emp_no,
第二列给出其manager的manager_no,
第三列给出该员工当前的薪水emp_salary,
第四列给该员工对应的manager当前的薪水manager_salary
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
输入描述:
无
输出描述:
emp_no |
manager_no |
emp_salary |
manager_salary |
---|---|---|---|
10001 |
10002 |
88958 |
72527 |
10009 |
10010 |
95409 |
94409 |
SELECT
d1.emp_no AS emp_no,
d2.emp_no AS manager_no,
d1.salary AS emp_salary,
d2.salary AS manager_salary
FROM
(
dept_emp d
INNER JOIN salaries s ON d.emp_no = s.emp_no
AND s.to_date = '9999-01-01'
) AS d1,
(
dept_manager m
INNER JOIN salaries s ON m.emp_no = s.emp_no
AND s.to_date = '9999-01-01'
) AS d2
WHERE
d1.salary > d2.salary
AND d1.dept_no = d2.dept_no;