CTF-web Xman-2018 第五天 WEB习题2

查看源码

http://120.24.86.145:8002/web2/

没什么可说的 直接查看源码就可以

带有转义的编码

http://120.24.86.145:8002/web3/

    进入之后看到一串奇怪的东西

KEY{J2sa42ahJK-HS11III&#125   //这是html js的转义的意思 直接alert(s)

百分号编码 

http://120.24.86.145:8002/web4/index.php

进去之后看到源码,源码里都是这种经过编码的百分号数据

escape采用ISO Latin字符集对指定的字符串进行编码。所有的空格符、标点符号、特殊字符以及其他非ASCII字符都将被转化成%xx格式的字符编码(xx等于该字符在字符集表里面的编码的16进制数字)。所以也不用多说,了解有这个知识点就可以,所以下面就直接解码了

<script>
var p1 = '%66%75%6e%63%74%69%6f%6e%20%63%68%65%63%6b%53%75%62%6d%69%74%28%29%7b%76%61%72%20%61%3d%64%6f%63%75%6d%65%6e%74%2e%67%65%74%45%6c%65%6d%65%6e%74%42%79%49%64%28%22%70%61%73%73%77%6f%72%64%22%29%3b%69%66%28%22%75%6e%64%65%66%69%6e%65%64%22%21%3d%74%79%70%65%6f%66%20%61%29%7b%69%66%28%22%36%37%64%37%30%39%62%32%62';
var p2 = '%61%61%36%34%38%63%66%36%65%38%37%61%37%31%31%34%66%31%22%3d%3d%61%2e%76%61%6c%75%65%29%72%65%74%75%72%6e%21%30%3b%61%6c%65%72%74%28%22%45%72%72%6f%72%22%29%3b%61%2e%66%6f%63%75%73%28%29%3b%72%65%74%75%72%6e%21%31%7d%7d%64%6f%63%75%6d%65%6e%74%2e%67%65%74%45%6c%65%6d%65%6e%74%42%79%49%64%28%22%6c%65%76%65%6c%51%75%65%73%74%22%29%2e%6f%6e%73%75%62%6d%69%74%3d%63%68%65%63%6b%53%75%62%6d%69%74%3b';
eval(unescape(p1) + unescape('%35%34%61%61%32' + p2));
</script>

一看就是百分号编码,拼接一下然后解码一下

function checkSubmit()
{
var a=document.getElementById("password");
if("undefined"!=typeof a)
{
if("67d709b2b54aa2aa648cf6e87a7114f1"==a.value)
     return!0;
alert("Error");
a.focus();
return!1
}
}
document.getElementById("levelQuest").onsubmit=checkSubmit;

在输入框中输入67d709b2b54aa2aa648cf6e87a7114f1得到flag

JSFUCK解码

http://120.24.86.145:8002/web5

在线的显示不出来,还是得用谷歌的控制台

这个东西应该有点印象,形式如下:

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有一个在线的加密网站,http://www.jsfuck.com/   

这是一段js代码,如果想要看看效果,把它放到你的控制台里面运行就可以了

Bp抓包 base64

http://120.24.86.145:8002/web6

进去是个网页提醒你快点,源码无信息,抓包发现响应头有flag字段,base64编码的

解码获得flag,最好使用python或者notepad++,在线有时候抽风

入门坑爹题

http://120.24.86.145:8007/web2/index.php

看起来特别难的注入,过滤很多字符

实际上是一个DS_STORE源码泄露,下载脚本ds_store_exp

py -2 ./ds_store_exp.py http://120.24.86.145:8007/web2/.DS_Store

下载到flag源码文件。

sha对比绕过

http://120.24.86.145:8002/web7

网页源码如下

 <?php
highlight_file('flag.php');
$_GET['id'] = urldecode($_GET['id']);
$flag = 'flag{xxxxxxxxxxxxxxxxxx}';
if (isset($_GET['uname']) and isset($_POST['passwd'])) {
    if ($_GET['uname'] == $_POST['passwd'])  //两者不能相同

        print 'passwd can not be uname.';

    else if (sha1($_GET['uname']) === sha1($_POST['passwd'])&($_GET['id']=='margin')) //sha1要相同 并且id参数值为margin

        die('Flag: '.$flag);

    else

        print 'sorry!';

}
?> 

要求uname和passwd经过sha1加密相等,这个不是碰撞,上网可以看到全世界就一例文件碰撞的。

我们传入不符合要求的数组,使得均返回false造成相等,传入id=margin

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转载自blog.csdn.net/iamsongyu/article/details/85011879
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