var i = 1;
var sum = 0;
for(var j=1;j<=100;j++){
sum = sum + i/j;
i = -i;
}
console.log(sum);
求1-1/2+1/3-1/4+1/5+...1/100
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转载自blog.csdn.net/xiamoziqian/article/details/85755499
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