A + B Again
hdu-2057
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 37848 Accepted Submission(s): 15333
Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Input
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Output
For each test case,print the sum of A and B in hexadecimal in one line.
Sample Input |
---|
+A -A
+1A 12
1A -9
-1A -12
1A -AA
Sample Output |
---|
0
2C
11
-2C
-90
问题分析
输入为16进制,输出也为16进制,二我们知道16进制是没有负数的,所以要用“-”-(hex)来表示一个16进制的负数
AC的c++代码 |
---|
#include<stdio.h>
#include<iostream>
using namespace std;
int main()
{
long long int a=0,b=0,c=0;
while (cin >> hex>>a >>hex>> b)
{
c = a + b;
if (c >= 0)
printf("%llX\n", c);
else
printf("-%llX\n", -c);
}
}