给定一个二叉树,返回它的 前序 遍历。
示例:
输入: [1,null,2,3]
1
\
2
/
3
输出: [1,2,3]
进阶: 递归算法很简单,你可以通过迭代算法完成吗?
C++用递归,python用迭代,迭代使用栈。
C++源代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> preorderTraversal(TreeNode* root) {
vector<int> res;
DFS(root, res);
return res;
}
void DFS(TreeNode* root, vector<int>& res){
if(!root) return;
res.push_back(root->val);
DFS(root->left, res);
DFS(root->right, res);
}
};
python3源代码:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def preorderTraversal(self, root: TreeNode) -> List[int]:
res = []
if root==None:
return res
s = [root]
while len(s)!=0:
node = s.pop()
res.append(node.val)
if node.right:
s.append(node.right)
if node.left:
s.append(node.left)
return res