LQB:序列求和

#include<iostream>
using namespace std;
int main(){
	unsigned long long n;
	cin>>n;
	unsigned long long sum=0;
	sum=(n+1)*n/2;
//	for(int i=1;i<=n;i++){
//		sum+=i;
//	}   //运行超时90分 
	cout<<sum;
	return 0;
} 

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转载自blog.csdn.net/weixin_41297324/article/details/88424461