设计思路:
- 换算成纳特(Knut)计算
编译器:C (gcc)
#include <stdio.h>
int main()
{
int g, s, k, p, a, change;
scanf("%d.%d.%d", &g, &s, &k);
p = g * 29 * 17 + s * 29 + k;
scanf("%d.%d.%d", &g, &s, &k);
a = g * 29 * 17 + s * 29 + k;
change = a - p;
if(change < 0){
change = -change;
printf("-");
}
printf("%d.%d.%d\n", change / (29 * 17), change / 29 % 17, change % 29);
return 0;
}