[LeetCode] Reordered Power of 2 重新排序为2的倍数



Starting with a positive integer N, we reorder the digits in any order (including the original order) such that the leading digit is not zero.

Return true if and only if we can do this in a way such that the resulting number is a power of 2.

Example 1:

Input: 1
Output: true

Example 2:

Input: 10
Output: false

Example 3:

Input: 16
Output: true

Example 4:

Input: 24
Output: false

Example 5:

Input: 46
Output: true

Note:

  1. 1 <= N <= 10^9



参考资料:

https://leetcode.com/problems/reordered-power-of-2/



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转载自www.cnblogs.com/grandyang/p/10747839.html